# Line slope calculator 10x+3y=30

**Straight line given by points A[0; 10] and B[3; 0]**

## Calculation:

**Slope-intercept form of line:**y = -3.3333x+10

**Canonical form of the line equation:**10x+3y-30 = 0

**Parametric form of the line equation:**

x = 3t

y = -10t+10 ; t ∈ R

**Slope:**m = -3.3333

**Slope angle of line: φ =**-73°18'3″ = -1.2793 rad

**X intercept:**x

_{0}= 3

**Y intercept:**y

_{0}= q = 10

**Distance line from the origin:**d

_{0}= 2.8735

**The length of the segment AB: |AB| =**10.4403

**Vector: AB =**(3; -10)

**Normal vector: n =**(10; 3)

**Midpoint of the segment AB: M =**[1.5; 5]

**Perpendicular Bisector equation:**3x-10y+45.5 = 0

**Vector OA = (0; 10) ; |OA| = 10**

**Vector OB = (3; 0) ; |OB| = 3**

**Scalar product OA .OB = 0**

**Angle ∠ AOB = 90° = 1.5708 rad**