anyone who can tell me how many gallons are in a cylinder 9.25"round by 24" long ? I'm making a gas tank and just wondering how much fuel this will have thanks in advance.
...according to my calculations, about 9 gallons...give or take...'course I may be wrong...your mileage may vary.
rethinking this...Unkl Ian may be closer...9.25x9.25x24=2053.5 c.i. divided by 231c.i./per gallon =8.88 gallons. But that doesn't work on round tanks. It would be less...
It's on Google...but if I remember right, it's height x depth x length divided by 231. There's 231 cubic inches in a gallon of liquid. A cylinder would be less volume than a square-sided tank.
<TABLE width="100%"><TBODY><TR><TD colSpan=2>[SIZE=+1]determining the number of gallons in a cylinder? This is how it was written [/SIZE] [SIZE=+1]V = pi r<SUP>2</SUP> h[/SIZE] [SIZE=+1]. does this mean pie, or 3.14 X radius squared, X the height? If so please use a standard 55 gal barrel (1' R & 3' H) for example? [/SIZE] [SIZE=+1]Thanks, Jim[/SIZE] <!-- InstanceEndEditable --></TD></TR><TR><TD width="13%"> </TD><TD colSpan=2> <!-- InstanceBeginEditable name="answer" -->[SIZE=+1]Hi Jim,[/SIZE] [SIZE=+1]You are correct about pi, it is approximately 3.1416. If the barrel has a one foot radius (r = 1) and a three foot height (h = 3) then the volume is[/SIZE] [SIZE=+1]V = pi r<SUP>2</SUP> h = 3.1416 1<SUP>2</SUP> 3 = 9.4248 cubic feet[/SIZE] [SIZE=+1]One cubic foot is 7.48 gallons(US) so 9.43 cubic feet is [/SIZE] [SIZE=+1]9.43 7.48 = 70.49 gallons[/SIZE] [SIZE=+1]I would measure your barrel again. I measured one I have and the diameter was approximately 22 inches so the radius is 11 inches which is 0.91667 feet. I also got a height of 33 inches or 2.75 feet. Thus I get, for a volume[/SIZE] [SIZE=+1]V = pi r<SUP>2</SUP> h = 3.1416(0.91667)<SUP>2</SUP> 2.75 = 7.26 cubic feet 7.26 7.48 = 54.3 gallons[/SIZE] </TD></TR></TBODY></TABLE>
Formula for round tanks Pi [3.1416] X the radius squared X lenght in inches. Divide that by 231 [number of cubic inches in a gallon] and that will give you capacity in US gallons.
"Pi x R squared" gives the area of the circle,multiply by the length to get the volume. 9.25 divided by 2 = 4.625 4.625 x 4.625 x 3.14 x 24 = 1611.99 cubic inches substitute that answer into this page,and you get 6.97 gallons. I guess i rounded off too much in my first calculation.
I would use the same formula that is used for figuring out engine size without multiplying x no of cylinders to find cubic inches. Bore x Bore x stroke x.7854 x no. of cylinders So you have 9.25 x 9.25 x 24 x .7854 = 1612.8188 Divided by 231 =6.9818995 gallons Hope this helps
The secret of math, is to keep your units in order. Here we have seen people using feet, and some using inches. OK, inches are 231 cubic inches in a US gallon of gas. No news here, as several people have quoted that number. Radius and Height in inches also, so we have 9.25 inches in diameter, so half would be the radius, or 4.625 inches squared, or 21.39 square inches times the height of 24 inches long times PI or 3.14 gives us about 1612 cubic inches. So 1612 cubic inches divided by 231 cubic inches per gallon, gives us 6.98 gallons. I'd say about 5 gallons without splashing all over the place. You can't fill it all the way up.
Wow, I didn't know we had that many mathmagicians here. I would have just filled a gallon jug with water and see how many times it took me to fill the tank up. I am no good at math.
Interestingly .7854 is PI/4 (3.14159 / 4) or 0.785398163 to be more exact. Here again, you have to be careful about units. 231 is for inches, therefore diameter must be in inches as well. If you square the diameter and divide by 4 and then multiply by PI it is the same as squaring the radius time PI, but just more work. Since the diameter is 2 times the radius, and you square it (2 x 2 = 4). And everyone can remember 3.14159 but who can remember .785398...
.7854 is easy to remember due to the fingering pattern on a typical calculator keyboard. 231 is easy cuz it's the cubic inch displacement of a Buick V6. Now, if someone could just tell me where the hell the 1/4" plate of stainless (6" x 14") got off to in my garage I'd be eternally grateful. I've wasted so much time looking for it that I finally put the project in a box and tossed it on the shelf....
Aren't all you guys the ones that told your teachers: "whatta I gotta learn this for? I ain't never gonna need it in the REAL world?" dj
It obivous that alot of folks here payed more attention in metal shop class than they did in math class..